Click Here to see the problem detail.
Solution

let,

Length of the flag = L,

Width of the flag = W,

Radius of the red circle = r;

so, according to question,

L:W=10:6

=>L/W=10/6

=>W/L=6/10

=>W=(6/10)*L

again,

L:r=5:1

=>L/r=5/1

=>r/L=1/5

=>r=(1/5)*L

Now, Area of entire flag= L*W

Area of red circle =∏*r2

Area of green part=L*W-∏*r2

Source Code
#include<stdio.h>
#include<math.h>
 
int main()
{
    double pi=acos(-1), l, w, r;
    int tc;
    scanf("%d",&tc);
    while(tc--)
    {
       scanf("%lf",&l);
       w=(l/10)*6;
       r=l/5;
       printf("%.2lf %.2lf\n",pi*r*r,(l*w)-(pi*r*r));
    }
 return 0;
}

 

Next Previous