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Will the statement cout.setf(ios::right) work or not?

#include <iostream> 
using namespace std;
void main()
{
     cout.width(5); 
     cout << "99" << endl;
  
     cout.setf(ios::left); 
     cout.width(5); 
     cout << "99" << endl;
  
     cout.setf(ios::right);
     cout << "99" << endl; 
}

cout.setf(ios :: right) will not work because width() function was not invoked before cout.setf(ios :: right)

State errors, if any, in the following statements.

• (a) cout << (void*) amount;
• (b) cout << put (“John”) ;
• (c) cout << width();
• (d) int p = cout.width(10);
• (e) cout.width(10).precision(3);
• (f) cout.setf(ios::scientific,ios::left);
• (g) ch = cin.get();
• (h) cin.get().get();
• (i) cin.get(c).get();
• (j) cout << setw(5) << setprecision(2);
• (k) cout << resetiosflags(ios::left lios::showpos);

• (a) missing
• (b) put ( ) a member function of ostream class. It is used to output a character. Hence it does not return any value; so cout<<(“John”); is not valid. Correction :
  cout.put (‘John’);
• (c) width ( ) function does not return any value. So cout <Correction : cout.width ( );
• (e) cout.width (10) precision (3); must be written separately
  cout.width (10);
  cout.preasion (3);
• (f) If you want to see output as scientfic format you can acheive this as follow:
  cout.setf (ios :: scientific, ios :: floatfield);   If you want to see output at left field you can achieve this as flows: cout.setf (ios :: left, ios :: adjustfield);
• (g) No error
• (h) cannot be concatenated;

Correction :
cin.get ( )
cin.get ( )

• (i) No error
• (j) No error
• (k) No error

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